Motorcycle Specifications:-

Top speed:- 170 Km/h

0-100 Km/h Time:- 3.5 Sec

Motor Used:- 20KW Cont / 50KW Peak // ~50Nm Continuous / 120Nm Peak

Tire Size:- 120/70-17 front and 160/60-17 rear

Motorcycle weight:- 190 Kg

Motor sprocket - 11T

Wheel sprocket - 64T

Assuming the rider weight as 60Kgs, calculate the maximum initial acceleration of the motorcycle?

Given,

Motor peak torque, Tmax =120 N-m

At the starting conditions, the motor delivers maximum torque to the wheels

Gear ratio, G= 64/11 = 5.818

The torque at the rear wheel = Tmax*G= 120*=698.16 N-m

Distance of the wheel center from the ground = Rim radius + height of the tyre

= (17/2*2.54) + (160/10 * 0.6)

= 31.19 cm = 0.312 m

Torque = Force * Perpendicular Distance

Force = 698.16/.312

F= 2237.69 N

For maximum initial acceleration, assume full weight on the rear wheel i.e., 190+60 = 250kg

From newtons 1st law of motion, F=ma

ð a= 2237.69/250

ð a=8.95 m/s2

Hence the maximum initial acceleration approximately .912g.